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Discussion > An invitation to BH Regulars to tear apart my beliefes about CO2

They use a geometric mean at T^4 for one number and an arithmetic mean of air temp for the other. It is not comparable, to me at least. Then there is rotation. It makes a difference. Imagine that the planet had a rotation rate of zero. One side hot, the other at 3K. That is not the same thing (average temp of a planet at that distance from the sun) as if the rotation was very fast, in which case temps would stabilize at..some number for each latitude. The moon is not at 255K. Now, the theory you state may well be right, but you can't just state it without looking at the questions of geometric vs arithmetic and rotation. There may be other factors which exist but didn't trigger my BS alarm.

I would not count down from TOA. I intuit that surface temps set altitude temps. I may be wrong. But surely there are measurements? How do they establish TOA as where the up and down radiation balance? By lapse rate? Or as they should by radiative integration?

I am not a physicist. The explanation presented may be fine. Of course it is only intended to describe ordinary interactions in the atmosphere as a basis. I am only questioning it to get it straight and maybe come upon some measurable confirmation.

May 18, 2014 at 7:32 PM | Registered Commenterrhoda

Rhoda

If you don't think there is any greenhouse effect at all you may be right but I think there is but not by the mechanism currently popular.

Incoming solar is full spectrum and therefore includes the radiation/absorption spectrum of GHG's. If you are going to start from somewhere, why not a temperature contour in the atmosphere - at least you are dealing with a single number.

The 'trapped heat' explanation requires that an addition of CO2 to the atmosphere reduces the radiating temperature (the energy imbalance searched for from the trapped heat conclusion) which is in defiance of the S-B Law. We have that experiment running at the moment. CERES satellites can't see any discrepancy that makes sense nor can they see a trend that reflects rising CO2 concentration. For me current GH theory is a busted flush. The whole thing needs to be audited by physicist engineers (no I'm not) or better still, started from scratch.

May 18, 2014 at 9:01 PM | Unregistered Commenterssat

rhoda

It is rather a circular argument using the TOA and tracing the lapse rate back down to the surface to calculate the temperature. This is where the CO2 moving TOA up and therefore theoretically increasing surface temperature argument comes from isn't it. How can you say that things like lapse rate would remain constant in that situation for example? It is all fine in giving a ballpark figure from a basic physical mechanism but has no predictive capability at all.

I've just been thinking again about the 1/5 of a cubic kilometre of ocean per person is in fact 200 million tonnes each isn't it? I could understand someone arguing that only say the top 200 metres get heated up by CO2 which is about 1/20 of that so even then each persons increased CO2 from having the aircon on has to heat up 10 million tonnes of water - clearly that is ludicrous as long as my sums were correct there. Also surely even if IR or increased surface temps could get into the ocean surely that is completely dwarfed by what the sun can dump into on a nice clear day (at some depth too)

May 19, 2014 at 6:32 PM | Unregistered CommenterRob Burton

TOA is not the same thing as average radiating height, not even close.
I haven't mentioned TOA except in this post.
The average radiating temperature is calculated from a physical Law.
Weather balloons, not climatology physics measure its height.
Lapse rates are not a controversial concept.

I bow out.

May 19, 2014 at 8:18 PM | Unregistered Commenterssat

"Lapse rates are not a controversial concept."

It isn't a constant though. Do you use a dry or moist adiabat for your lapse rate, considering moisture content and vary so much in time and location.

May 19, 2014 at 9:00 PM | Unregistered CommenterRob Burton

Pity ssat is bowing out, I have always wondered about where the effective blackbody surface is located for a planet with an atmosphere.

Imagine that you are in space and you measure the radiation emitted by the earth. The SB theory lets you calculate the temperature of the earth. That suggests it is -18.

We know that the surface is about 15 degrees. The climate scientists tell us that GHG is responsible for the difference of 33 degrees.

There are a number of assumptions in this tiny bit of theory.

May 19, 2014 at 9:13 PM | Unregistered CommenterSchrodinger's Cat

My apologies - I brought the frustrations of my day to a place where I generally relax.

SC. Yes, I have a problem with that tiny bit of theory too. S-B temperature for Earth with its albedo is -18. The 33 degree difference you mention, we are told, is the greenhouse effect and ascribed entirely to radiative effects within the atmosphere. However, lapse rate would add somewhere between 5 to 10 degrees/km to that. If, over a dessert, the -18 occurs at 3km above the surface then the surface (Stephenson screen height) temperature would be ~30 degrees higher and explain the greenhouse effect by an entirely different phenomenon.

Perhaps one of the commenters that Dung has encountered that don't believe we should question the science would care to explain the fault in the above? Or anybody, whatever their disposition?

May 20, 2014 at 7:11 AM | Unregistered Commenterssat

Here's a question. Do radiosondes actually observe a uniform lapse rate in real life? Accurate to three figures? Is it the usually accepted numbers, or does it vary in real life?

May 20, 2014 at 8:04 AM | Registered Commenterrhoda

I think we established here a couple of years ago that the average surface temp comparison with the S-B average temp does not work for the moon, where there is no TOA and no lapse rate. If it doesn't work for a piece of rock, it will not work for a wet planet with an atmosphere. The 33 degree argument is therefore bogus. Now that doesn't disprove AGW or CAGW, it just means that you can't illustrate it that way.

May 20, 2014 at 8:17 AM | Registered Commenterrhoda

Rhoda, I think this TOA thing is misleading. Assume the Earth has a constant surface (not near-surface) temperature, forget the sun but keep the radiative atmosphere. Seen from space the average radiating temperature would occur at some height in the atmosphere, would be lower than the surface temperature and the difference would be the lapse rate. No?

May 20, 2014 at 8:36 AM | Unregistered Commenterssat

A comment by R G Brown at WUWT. Is the climate computable?:


The trouble is that water vapor is literally a two-edged sword. As vapor, it is the strongest greenhouse gas in the atmosphere by (IIRC) around an order of magnitude, so increasing water vapor can and does measurably increase the GHE — a lot, when considering dry air versus saturated air. In arid deserts, temperatures skyrocket during the day and plummet at night because of the absence of a water vapor driven GHE — CO_2 alone isn't nearly enough to keep upward facing surfaces from rapidly losing their heat due to radiation. In very humid tropical climates, the nights are consistently warm because of the GHE.

However, water vapor is also the mediating agent for two major cooling mechanisms. One is the bulk transport of latent heat — sunlight and LWIR hit the sea surface and cause rapid evaporation of surface molecules of water. Wind blows over the ocean surface, stripping off water molecules as it goes. This evaporated water has a huge heat content relative to liquid water — the latent heat of vaporization. As the warm water vapor is carried aloft by convection, it carries the heat along with it.(...)

(...)
(...)
(...)

This is the kind of thing that the models are supposedly trying to model, but they perforce replace all of the small-length scale detail of this description with presumptive averages over cells 100-300 km square (where weather phenomena such as thunderstorms are order of 1 to 10 km square, where the details of front structure and development are much finer than this). They are excruciatingly tuned to aerosol levels and albedo — they have to be to stabilize anywhere near the correct/observed temperatures and preserve the central tenet that CO_2 causes X amount of baseline warming that is on average augmented by additional water vapor.

This last assumption is finally dying a quiet and well deserved death. AFAIK, it is due to Hansen, who in his original papers predicting disaster assumed universally positive water vapor feedback (and for no particularly scientifically motivated reason that I can see, hypothesized truly absurd levels of water vapor feedback that doubled or tripled the CO_2-only warming of his then very simple models).

(...)
(...)

May 22, 2014 at 8:47 AM | Registered CommenterMartin A

ssat, put like that I cannot argue against it. But I think all of that is an observed rather than a predicted state. By which I mean that some change of IR absorption/reradiation has some predictable effect on TOA height or that the lapse rate is some fixed value which works to set the surface temp. I'm not sure .I'm getting this over properly. I think what happens at the surface sets surface temp, not something that happens at the tropopause.

However, I am quite sure that there is no 'correct' temp for a body at some distance from the sun independent of its rotation rate and the conductive characteristics of the surface and thus no way to quantify 'greenhouse effect' at 33K or any other number. Arguments based on that are bogus, in my completely unqualified opinion.

May 22, 2014 at 10:21 AM | Registered Commenterrhoda

Rhoda, the S-B equation applies to a body at some temperature above absolute zero. For a body externally and asymmetrically heated while it is rotating, who knows if it applies. But assume it does because it is the cornerstone of GE. Let us remind ourselves of GE. From WikiP;

If an ideal thermally conductive blackbody were the same distance from the Sun as the Earth is, it would have a temperature of about 5.3 °C. However, since the Earth reflects about 30% of the incoming sunlight, this idealized planet's effective temperature (the temperature of a blackbody that would emit the same amount of radiation) would be about −18 °C. The surface temperature of this hypothetical planet is 33 °C below Earth's actual surface temperature of approximately 14 °C. The mechanism that produces this difference between the actual surface temperature and the effective temperature is due to the atmosphere and is known as the greenhouse effect.

Those numbers are all averages and come from S-B except for the 14 °C which comes from averaging of temperature measurements. So, having determined the average radiating temperature for Earth as −18 °C, the measured 14 °C at the bottom of atmosphere is declared as being a newly discovered radiative effect within the atmosphere. This is a jump of logic that I don't understand - why would the average radiating temperature be located at the bottom of atmosphere? Would it not make more sense to conclude that it exists at the average −18 °C height within it? It is so easy to check: send up a weather balloon and if the −18 °C height coincides with what might be expected by lapse rate from the Stephenson screen temperature directly below it then you have the answer that the 14 °C average is down to that phenomenon. There is no need for any other and much more complex theory.

Oh, and one more thing: S-B Law doesn't state j*=σT^4 except for CO2. It makes no exceptions at all.

So there you have it - my understanding or misunderstanding in a nutshell.

May 22, 2014 at 8:55 PM | Unregistered Commenterssat

S_B talks about a body. Not a planetary body, some discrete thing at some temperature and with some given emissivity. You'd have to integrate all those discrete things to get the total radiation. The geometric average at t^4 is not the same number as the arithmetic average. It can be where all the temps are the same, but as soon as you get varying temps the higher temps radiate far more than the lower ones. X plus deltax to the power four is rather more different to x^4 than x minus delta x to the fourth. Whereas the arithmetic average of x plus deltax and x minus delta x is x. When you get some S-B number from a body of varying temps the same holds. The higher temps out-radiate the lower. You just can't compare it to a planetary average temp got from thermometers because it isn't the same thing. That's before the rotation is taken into account. Rotation will affect the amount by which the temps vary. Slow and temps differ a lot over the surface. Fast and they don't differ so much. But the S-B number will be different depending on the rate.

Besides which , Nasa has measured temps on the moon and they do not match the S-B number for that uncomplicated body.

May 22, 2014 at 9:17 PM | Registered Commenterrhoda

rhoda, I absolutely and completely agree with you that S-B may not apply, I said that in my second sentence. It could be the first big thing that climate science got wrong. However, if, as they have done, go on to compound that error with more error, there has to be a weak-spot that is easily attacked. There are no numbers for a planetary body that can be used for that. We simply don't know, and possibly never will directly, if your objections are apposite. Back to WikiP;

The mechanism that produces this difference between the actual surface temperature and the effective temperature is due to the atmosphere and is known as the greenhouse effect.

My objection with this is that it is linked to some idea of 'trapping heat' while other, well understood effects are ignored. This is not to say that I don't think radiative gasses have an effect - an only nitrogen atmosphere would have its average radiating height coincident with the planet surface. But add radiative gasses and it would not.

May 22, 2014 at 10:22 PM | Unregistered Commenterssat

S-B Law doesn't state j*=σT^4 except for CO2. It makes no exceptions at all.

Er, does it not assume the planet is a black body? So that if the radiation is being done by gases such as CO2 (which arent "black") the law won't apply precisely?

May 22, 2014 at 10:46 PM | Registered CommenterMartin A

Martin A: S-B is modified for a grey body to j*=εσT^4 where ε=emissivity. It applies to absorption and radiation equally. S-B for any value of ε, including 1, requires that no heat is trapped. CO2 is not an exception.

May 23, 2014 at 7:35 AM | Unregistered Commenterssat

ssat - My understanding of these things is about that of the average schoolboy, so I'm asking diffidently.

"Martin A: S-B is modified for a grey body to j*=εσT^4 where ε=emissivity. It applies to absorption and radiation equally."

yes, of course.

" S-B for any value of ε, including 1, requires that no heat is trapped. "

I'm not sure what that means. [Perhaps because I've only heard Met Office (and other) 'climate scientists' use the phrase "traps heat" ?] Maybe you are referring to the fact that a black (or grey) body finding itself in with constant intensity of incoming radiation will heat up until the power it is radiating equals the power it is absorbing?

What I had in mind was a body where ε is a function of wavelength. For example a thin balloon containing nothing but CO2. I'm not sure that j*=σT^4 precisely for such a body.

May 23, 2014 at 10:07 AM | Registered CommenterMartin A

Martin A: Trapping heat is indeed what we are told by our betters (schoolboy diffidence there) - its not my concept. I just don't buy it. A ball(oon) of CO2 in space would heat up by absorbing solar radiation at its narrow active frequencies - solar radiation is full spectrum. It would radiate at those same frequencies and attain a stable temperature when, as you say, the power it is radiating equals the power it is absorbing. For it to 'trap heat' the temperature it attains in equilibrium would have to be higher than S-B states. I don't believe it would defy S-B. Have you come across something that shows it would?

May 23, 2014 at 10:45 AM | Unregistered Commenterssat

ssat - yes, obviously a ball(oon) of CO2 in space will warm up until it the power it radiates equals the power it absorbs and its temperature is stable.

" I don't believe it would defy S-B. Have you come across something that shows it would?"

I don't have any physics books available to me. However here is my understanding:
1. Planck's formula gives the intensity of radiation from a black body as a function of wavelength.
2. The Stefan-Boltzmann law is derived (I believe) by integrating Planck's formula over all wavelengths.

The radiation from gases such as CO2, as a function of wavelength, is given by measured curves which are full of fuzzy lines and which are quite different from a plot of Planck's formula. So when you integrate the curve for CO2, you'll end up with something other than S-B.

Does that make sense or have I missed something?

May 23, 2014 at 12:29 PM | Registered CommenterMartin A

"I can't say for certain, but I remember as a lad reading that the temperature on Venus was caused by "greenhouse gases" and CO2 was the major cause - I believe a young Carl Sagan was responsible for this theory."

You can read Sagan's paper here. Sagan calculates it by determining the height of the clouds = the average altitude of emission to space, and the lapse rate. The surface is warmer than the clouds by the product of the two. That is to say, Sagan used the emission altitude/lapse rate mechanism.

"They use a geometric mean at T^4 for one number and an arithmetic mean of air temp for the other. It is not comparable, to me at least."

Quite right. The one-dimensional model is a back-of-envelope simplification that is only the starting point for understanding. To get a proper answer, you have to work out the temperature of every layer of atmosphere at every location on the globe, accounting for the opacity of the air above it, and sum. That is to say, you need a climate model.

If you want an explanation you can understand and test for yourself, it will be simplified. If you want to build your own climate model, go ahead. I'd definitely encourage people to try.

"I would not count down from TOA. I intuit that surface temps set altitude temps. I may be wrong."

First, it's not TOA, it's the average altitude of IR emission to space, which is only about 5 km up. Second, the lapse rate adjustments do actually propagate both upwards and downwards - it's more like the way the surface of a body of water with inflows and outflows approaches horizontal. So imagine a lake with a sloping bottom, with rivers pouring in at one end and another river pouring out through a narrow V-shaped channel at the other end. The V shape means the higher the water level, the faster it flows.

What determines the depth of water at any point in the lake is the slope of the lake bed (the lapse rate), and the amount of water in the lake, which is determined by the inflow (absorbed sunlight, taking account of cloudiness) and the outflow (Stefan-Boltzmann emission to space). If more water enters than can escape through the bottom of the V, the water level rises (if more heat is absorbed than emitted, the temperature rises). If less water enters than can escape through the top of the V, the water level falls (the atmosphere cools). So the depth of water in the lake at the outlet is pushed towards the point where the amount that escapes balances the input.

But the depth of water elsewhere in the lake depends on the slope of the bottom relative to the outlet, and how far from the outlet you are (the lapse rate, times the difference in altitude). It's perfectly true that all the water where you are comes from the inlets, and the levelling of the surface is driven by the water piling up close to the inlets and spreading out. But what *controls* the level is difference between input and output. The drop in level close to the output also spreads out across the surface, although the water there is flowing in the opposite direction to the influence.

"How do they establish TOA as where the up and down radiation balance? By lapse rate? Or as they should by radiative integration?"

In reality, it's not so simple because you also have horizontal energy transfer. Convection carries heat from the equator towards the poles, so at any given location you also have massive heat flows that are not accounted for radiatively. But yes, as I understand it the climate models use a joint radiative-convective approach that includes radiative integration, and no, they don't assume a fixed lapse rate, but (crudely) model the physics of convection.

"This is where the CO2 moving TOA up and therefore theoretically increasing surface temperature argument comes from isn't it. How can you say that things like lapse rate would remain constant in that situation for example?"

Because the adiabatic lapse rate is a thermodynamic property of gases. For an ideal gas, the lapse rate is equal to the acceleration due to gravity divided by the specific heat capacity of air at constant pressure. Neither of those are things that are likely to change. There is a common adjustment to account for latent heat from the condensation of water vapour, which is really a separate bit of physics but has the same sort of dependence on altitude, so it makes things simpler to merge the two effects into one number. This part of the effect depends on humidity.

The humidity *does* change, and this does indeed change the moist adiabatic lapse rate. This is in fact the putative cause of the tropical hotspot - the one that's missing. The theory is that a warmer atmosphere will be moister, which reduces the lapse rate, and the shallow curve makes levels below the average emission altitude cooler (cancelling part of the warming and therefore a negative feedback) and levels above it warmer (i.e. the hotspot). The missing hotspot is saying that the lapse rate *hasn't* changed when we expected it to - quite likely because the water vapour feedback isn't as strong as the models think.

"However, I am quite sure that there is no 'correct' temp for a body at some distance from the sun independent of its rotation rate and the conductive characteristics of the surface and thus no way to quantify 'greenhouse effect' at 33K or any other number."

True. It's an approximation.

"What I had in mind was a body where ε is a function of wavelength. For example a thin balloon containing nothing but CO2. I'm not sure that j*=σT^4 precisely for such a body."

It's not. It's an approximation. It's like asking for 'the density' of the human body, to see if a person will float in water. Different bits of the body have different densities, and thus giving any single number is always 'wrong'. But if you pick a weighted average of the many different densities involved, that will be somewhere in the middle between the highest and lowest densities, you can do the maths as if the body was all of a constant uniform density and get a valid answer. It just makes the sums easier.

To get an exact answer, you do have to integrate the absorption as a function of wavelength, which is what programs like MODTRAN do.

May 23, 2014 at 2:21 PM | Unregistered CommenterNullius in Verba

Isn't the lapse rate derived from (or supported by) ideal gas laws? Isn't the real-life situation less than ideal. For instance, no conservation of energy within the gas law where there is radiation in and out.


What does the earth look like from space using a thermal imaging system? A fuzzy ball of relatively uniform temp? A glittering jelly of large differences? That would be the test of the TOA explanation. (I know these are largely illustrations to explain GHE to the simple. But I'm simple and the explanations sound a bit funny. to me. That's why when someone parrots the 33K to me I reject it. I know that one isn't useful. )

NiV, why do you say that level is at 5Km. I thought it to be at the tropopause. Above which there is no lapse rate. Do the gases stop obeying the law at 36000 feet?

Here's another. What's the range of measured lapse rates from the balloons? How much do they vary from the ideal?

May 23, 2014 at 4:35 PM | Registered Commenterrhoda

Martin A: I don't recall greenhouse theory concerning itself with some amplification effect of irradiated CO2 ( a greater T than suggested by S-B), rather, I thought it to be based upon CO2 (+ the rest of the GH gasses) re-radiating from the atmosphere back to the surface. If I have misunderstood that then please put me out of my misery!

As an alternative to the WikiP definition of greenhouse effect I have come to the conclusion that a planet without such an effect has its average radiating height of the S-B derived temperature coincident with its surface and a planet with such an effect has its average radiating height of the S-B derived temperature above its surface. Applying lapse rate to the second scenario would account for at least some of the additional 33°C, possibly all. Both rhoda's and your points may be germane in the real world but is that the same world that climate science inhabits?

Why am I posting on this thread (rhetorical). Basically I am asking the same question as Dung. By doing so I am trying to support him in his quest.

May 23, 2014 at 5:10 PM | Unregistered Commenterssat

NiV: Isn't calculating what radiates to which inside the atmosphere just examining how greenhouse gasses distribute energy throughout the system and have in fact no bearing at all on average radiating temperature?

May 23, 2014 at 5:22 PM | Unregistered Commenterssat

ssat - all (*all*) I was saying is that the fourth power law does not apply precisely to CO2, whereas it does to a black body. I did not intend to imply that that increases (or decreases for that matter) the GHE. It's just my nature to look at categorical statements and then to try to think of exceptions.

Here is my understanding. I don't think it will help you as I tend to take a view (similar to what I understand rhoda's view is): if a model of a physical effect has not been confirmed by detailed measurements, then it's just speculative hand-waving at best.

The very simple model of a spherical and perfectly conducting black body surrounded by a thin shell of greenhouse gas is so simple that its analysis cannot be doubted. However, it is such a simple model that it provides, at best, a plausibility argument that the Earth benefits from a greenhouse effect.

From then on, there is nothing but computer models. Judith Curry asked what there was in the way of a detailed explanation of the GHE that, say, a physics graduate could follow. She concluded there was none - just computer models.

I've stated many times on BH my belief that an unvalidated model is no more than an illustration of a hypothesis (or a bunch of them stewed up together in the case of computer models). My own personal conclusion is therefore that nobody understands the GHE and that discussions of the details of how it works in reality are likely to go round in endless circles.

As confirmation of my view: If I were incorrect, surely there would be a downloadable pdf from the Met Office with a title along the lines "A Detailed Explanation of the Greenhouse Effect" that would answer all of Dung's questions?

May 23, 2014 at 6:21 PM | Registered CommenterMartin A